Write a program to print 1 to 100 using an exit jump statement in java

Hello guys, welcome to lingarajtechhub.com . Today we are going to discuss print 1 to 100 using an exit jump statement in java.

Code:

package com.exit1.java;

public class Exit {

	public static void main(String[] args) {
	int i;
	for(i=1;i<100;i++)
	  {
		if(i==94)
		{
		System.exit(0);
		}
		System.out.println(i);
	  }
  }

Line-1:

package com.exit1.java;

It is a java package , this package is created in a java project and it contains classes inside the package.

Line-3:

public class Exit

Here ” Exit ” is the class-name , class is a template used to create objects & class-name first letters must be capital . It is public means we can access this data in another project.

Line-5:

public static void main(String[] args)

It is a main method in which we can execute a program.

public : It is an access modifier. The main() is public because we can access main() outside of the class , if main() can’t be public then JVM(Java Virtual Machine) can’t be called main() & code can’t be executed.

Static : static is a keyword in which the main method has to be static in which JVM can load the class into memory and call the main method without creating an instance.

Void : Void is a data type. It means no return type.

main(): Main is a function.

String [] args : string means collection of characters ,String[] args represents a collection of Strings that are separated by a space and can be typed into the program on the terminal directly.

Line-6:

int i

Here int is an integer data type. ‘ i ‘ is the variable .

Line-7:

for(i=1;i<100;i++)

In this program use a for loop .(i=1;i<=100;i++) here apply the logic .It means i value started from 1, continue this loop 100 times and increment value 1 continuously while the program is not ending.

Line-9: