Write A Program To Check Entered Number Is A Spy Number Or Not Through C Program

In this post I am going to discuss a program called, Entered Number A Spy Number Or Not.

What is Spy Number?

When you enter a natural number like 1124 then sum up its digit is equal to product of all the digits. Like,

//Example:
Suppose n=1124
Product of digits on prod=(1 * 1 * 2 * 4) = 8
Sum of digits on sum=(1 + 1 + 2 + 4) = 8
Here, sum==prod both product and sum are equal.
Output: Spy Number

Input : 1412
Explanation : 
sum = (1 + 4 + 1 + 2) = 8
product = (1 * 4 * 1 * 2) = 8
since, sum == product == 8
Output : Spy Number

Input : 132
Explanation : 
sum = (1 + 3 + 2) = 6
product = (1 * 3 * 2) = 6
since, sum == product == 6
Output : Spy Number

C program to check number is a spy number or not(Using For Loop):

#include <stdio.h>

int main()
{
    int n,s=0,p=1,d;
    printf("Enter any no ");
    scanf("%d",&n);
    for(;n>0;)
    {
        d=n%10;
        s=s+d;
        p=p*d;
        n=n/10;
    }
    printf("Sum of digits = %d Product of digits = %d\n",s,p);
    if(s==p)
        printf("Number is a Spy Number");
    else
        printf("Number is not a Spy Number");
    return 0;
}
Case-1:
Output:
Enter any no 253
Sum of digits = 10 Product of digits = 30
Number is not a Spy Number
Case-2:
Output:
Enter any no 123
Sum of digits = 6 Product of digits = 6
Number is a Spy Number

C program to check number is a spy number or not(Using While Loop):

#include <stdio.h>

int main()
{
    int n,s=0,p=1,d;
    printf("Enter any no ");
    scanf("%d",&n);
    while(n>0)
    {
        d=n%10;
        s=s+d;
        p=p*d;
        n=n/10;
    }
    printf("Sum of digits = %d Product of digits = %d\n",s,p);
    if(s==p)
        printf("Number is a Spy Number");
    else
        printf("Number is not a Spy Number");
    return 0;
}
Case-1:
Enter any no 321
Sum of digits = 6 Product of digits = 6
Number is a Spy Number
Case-2:
Enter any no 365
Sum of digits = 14 Product of digits = 90
Number is not a Spy Number

C program to check number is a spy number or not Using Function Without Passing Arguments:

#include <stdio.h>
void check()
{
    int n,s=0,p=1,d;
    printf("Enter any no ");
    scanf("%d",&n);
    while(n>0)
    {
        d=n%10;
        s=s+d;
        p=p*d;
        n=n/10;
    }
    printf("Sum of digits = %d Product of digits = %d\n",s,p);
    if(s==p)
        printf("Number is a Spy Number");
    else
        printf("Number is not a Spy Number");
}

int main()
{
    check();
    return 0;
}
Case-1:
Enter any no 312
Sum of digits = 6 Product of digits = 6
Number is a Spy Number
Case-2:
Enter any no 145
Sum of digits = 10 Product of digits = 20
Number is not a Spy Number

C program to check number is a spy number or not Using Function Passing Argument

#include <stdio.h>
void check(int n)
{
    int s=0,p=1,d;
    while(n>0)
    {
        d=n%10;
        s=s+d;
        p=p*d;
        n=n/10;
    }
    printf("Sum of digits = %d Product of digits = %d\n",s,p);
    if(s==p)
        printf("Number is a Spy Number");
    else
        printf("Number is not a Spy Number");
}

int main()
{
    int n;
    printf("Enter any no ");
    scanf("%d",&n);

    check(n);
    return 0;
}
Case-1:
Enter any no 965
Sum of digits = 20 Product of digits = 270
Number is not a Spy Number
Case-1:
Enter any no 231
Sum of digits = 6 Product of digits = 6
Number is a Spy Number

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Lingaraj Senapati
Hey There! I am Lingaraj Senapati, the Co-founder of lingarajtechhub.com My skills are Freelance, Web Developer & Designer, Corporate Trainer, Digital Marketer & Youtuber.
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