How to print a given year calendar in Python without calendar module can be a bit more complex, as you’ll need to calculate the days and months yourself. However, it’s certainly possible. Here’s a simplified example of how you can print a one-year calendar using basic Python:
def is_leap_year(year):
"""Check if a year is a leap year."""
return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)
def days_in_month(year, month):
"""Get the number of days in a month."""
if month in {1, 3, 5, 7, 8, 10, 12}:
return 31
elif month in {4, 6, 9, 11}:
return 30
elif month == 2:
return 29 if is_leap_year(year) else 28
def print_month(year, month):
"""Print the calendar for a specific month."""
month_name = ["January", "February", "March", "April", "May", "June", "July",
"August", "September", "October", "November", "December"]
print(f"{month_name[month - 1]} {year}")
print("Su Mo Tu We Th Fr Sa")
# Find the day of the week for the first day of the month
first_day_weekday = (year + (year // 4) - (year // 100) + (year // 400) +
[0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4][month - 1]) % 7
for _ in range(first_day_weekday):
print(" ", end=" ")
for day in range(1, days_in_month(year, month) + 1):
print(f"{day:2} ", end=" ")
first_day_weekday += 1
if first_day_weekday == 7:
print()
first_day_weekday = 0
print("\n")
def print_year_calendar(year):
"""Print the calendar for the entire year."""
for month in range(1, 13):
print_month(year, month)
# Get user input for the year
year = int(input("Enter the year: "))
print_year_calendar(year)
