In this post I am going to solve one problem **power of a number using pow function**.

So,

**How to solve this problem?**

Here user first input two numbers and find there power using pow() function. So, here how to find power of two number in** C Programming**. How to use pow() function in **C Programming**.

**Example:**

```
Input
Enter base: 5
Enter exponent: 2
Output
5 ^ 2 = 25
```

## Program to Find power of a number:

/** * C program to find power of any number */ #include <stdio.h> #include <math.h> // Used for pow() function int main() { double base, expo, power; /* Input two numbers from user */ printf("Enter base: "); scanf("%lf", &base); printf("Enter exponent: "); scanf("%lf", &expo); /* Calculates base^expo */ power = pow(base, expo); printf("%.2lf ^ %.2lf = %.2lf", base, expo, power); return 0; }

**Output:**

```
Enter base: 5
Enter exponent: 3
5 ^ 3 = 125
```

Here %.2lf is used to to print fractional value up to 2 decimal places.

**Step-1:**

`line no. -1 to 3 is a comment to "find power of any number"`

**Step-2:**

`line no. 5 and 6 used header files "<stdio.h> <math.h>" line no. 5 for scanf() and printf() and line no. 6 used for pow() "<math.h>"`

**Step-3:**

`line no. 8 "int main()" execution begins here.`

**Step-4:**

`line no. 13 and 14 used for print on console (printf("Enter base: ");) and take input from user(scanf("%lf", &base);)`

**Step-5:**

```
line no. 15 and 16 used for input expo by help of [
printf("Enter exponent: "); => used for console before take input
scanf("%lf", &expo); ]
```

**Step-6:**

```
line no 18 used for comment and 19 used for solving the problem by expression [/* Calculates base^expo */
power = pow(base, expo);
]
```

**Step-7:**

```
line no 21 print by help of printf()
[printf("%.2lf ^ %.2lf = %.2lf", base, expo, power);] here we used %.2lf for fractional value up to 2 decimal places.
```

**Step-8:**

`return 0; //successful execution by return to main()`

Please comment and share this post if you find valuable information and wants to contribute please **WhatsApp** us.